Question

Which is the equation of a hyperbola with directrices at x = ±2 and foci at (4, 0) and (−4, 0)?

Answer #1

Find the standard form of the equation of the hyperbola
satisfying the given conditions. Foci at (-4,0) and (4,0);
vertices at (3,0) and (-3,0)

An equation of a hyperbola is given.
x^2/ 9 - y^2//49=1
(a) Find the vertices, foci, and asymptotes of the hyperbola.
(Enter your asymptotes as a comma-separated list of equations.)
vertex
(x, y)
=
(smaller x-value)
vertex
(x, y)
=
(larger x-value)
focus
(x, y)
=
(smaller x-value)
focus
(x, y)
=
(larger x-value)
asymptotes
(b) Determine the length of the transverse axis.
(c) Sketch a graph of the hyperbola.

1. Find an equation for the hyperbola described. Graph the
equation. Foci: (3,4) and (3,10) Vertex: (3,8)
2. Find an equation for the ellipse. Graph the equation. Center
at (1,1); focus at (1,9); contains the point (5,1)

Find the hyperbola equation that satisfies the given conditions
:
Foci: (1,8)
(1,−12); vertices are 4 units apart.

Identify the following as the equation on a parabola, ellipse,
or hyperbola:
x^2-16y^2+64y-208=0
a) state what it is
b) depending on what it is, find the direction, coordinates of
the center, vertex or vertices, foci, and the equation of
asymptotes.

find the standard form of the equation of the hyperbola
satisfying the given conditions. Foci at (-6,0) and (6,0); vertices
at (4,0) and (-4,0)

Write an equation for the hyperbola with vertices (–10, 1) and
(6, 1) and foci (–12, 1) and (8, 1).?

Find an equation for the hyperbola that satisfies the following
conditions.
Vertices (−1,1) and (1,1); foci 16 units apart .
1=

Find the center, foci, vertices, and eccentricity of the
hyperbola, and sketch its graph
y^2 - 16 x^2 + 64 x - 208 = 0
Please solve all the following needs.

find the vertices,foci and asymptotes of the hyperbola and
sketch its graph y^2/25-x^2/9=1
show all work and step

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