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1. To test this series for convergence ∞∑n=1 n /√n^3+1 You could use the Limit Comparison...

1. To test this series for convergence
∞∑n=1 n /√n^3+1
You could use the Limit Comparison Test, comparing it to the series ∞∑n=1 1 /n^p where p=

2. Test the series below for convergence using the Ratio Test.
∞∑n=1 n^5/0.5^n
The limit of the ratio test simplifies to lim n→∞|f(n)| where
f(n)=   
The limit is:

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