Question

tan(t)=1/tan(t) in the interval 0≤t≤2π

Answer #1

1. Find all angles
θ,0≤θ≤2π
(Double angle
formula, To two decimal places)
a) Tan theta
= 0.3, b) cos theta = 0.1, c) sin theta = 0.1,
d) sec theta
= 3

Proof For 0 < t < pi/2
2sin(t) + tan(t) >3t

Solve 6cos2(t)+sin(t)−4=06cos2(t)+sin(t)-4=0 for all solutions
0≤t<2π0≤t<2π

1.Find all solutions on the interval [0, 2π)
csc (2x)-9=0
2. Rewrite in terms of sin(x) and cos(x)
Sin (x +11pi/6)

If θ is in the interval [0, 2π) and cos(θ) = √ 2/2 , then θ must
be π/4 .
State true or false.

y'' + 4y' + 5y = δ(t − 2π),
y(0) = 0, y'(0) = 0
Solve the given IVP using the Laplace Transform. any help
greatly appreciated :)

Find all solutions to 2 cos t = 0.35 for 0 ≤ t ≤ 2π Give
answers correct to 3 decimal places. Give answers in degrees.

1.Solve 3cos(2α)=3cos2(α)−23cos(2α)=3cos2(α)-2 for all solutions
on the interval 0≤α<2π0≤α<2π
αα =
Give your answers accurate to at least 3 decimal places, as a list
separated by commas
2.Solve 7sin(2w)−5cos(w)=07sin(2w)-5cos(w)=0 for all solutions
on the interval 0≤w<2π0≤w<2π
ww =
Give your exact solutions if appropriate, or solutions accurate to
at least 3 decimal places, as a list separated by commas
3.Solve 7sin(2β)−2cos(β)=07sin(2β)-2cos(β)=0 for all solutions
0≤β<2π0≤β<2π
ββ =
Give exact answers or answers accurate to 3 decimal places, as
appropriate
4.Solve...

In the interval −π < t <
0, f(t) = 1; and for 0 < t
< π, f(t) = 0. f(t) = f(t+2 π)
Find the following for f(t) as associated with the Fourier
series:
a0 =?
an =?
bn =?
ωo =?

For 2y' = -tan(t)(y^2-1) find general solution (solve for y(t))
and solve initial value problem y(0) = -1/3

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