Question

Part 2 of 13 - Oxford

According to a joint study conducted by Oxford's Environmental Management Department and a state government agency, the concentration of carbon monoxide in the air due to automobile exhaust t years from 2009 is given by $$C(t)=0.01(0.2t^2+4t+64)^{\frac{2}{3}}$$ in parts per million (ppm), where t=0 represents 2009.

Question 12 of 59

1 Points

At what rate is the carbon monoxide level changing in 2010?

• A. $$0.0093$$
• B. $$0.0072$$
• C. $$\text{none of the other answers}$$
• D. $$5.7689$$
• E. $$0.8959$$

Answer 1