F(g(x))=x^4 and G'(1)=2 find F'(g(1))
Answer: 2
Solution:
Step 1. Chain Rule.
Step 2. Find derivative of F(G(x)) = x4
. Using
Step 3. Put x=1.
Step 4. Put the values in chain rule.
[F(G(1))]' = F'(G(1)).G'(1)
4 = F'(G(1)). 2
F'(G(1))= 4/2 = 2
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