Question

- A particle moves along a coordinate line so that its velocity
at time
*t*is ?(?) = ?^{2}− 2? m/s. Find the total distance travelled by the particle during the first 4 seconds.

Answer #1

A particle that moves along a straight line has velocity v ( t )
= t^2e^− 2t meters per second after t seconds. How many meters will
it travel during the first t seconds (from time=0 to time=t)?

Find the distance travelled by the particle during the first 4
seconds when a particle moves in a straight line with a velocity at
time t given by t-2.
I need the answer ASAP

A particle moves along a line with velocity v(t)=(3 -
t)(2+t), find the distance traveled during the time interval [0,
1].

The function s(t) describes the position of a particle moving
along a coordinate line, where s is in feet and t is in
seconds.
s(t) = 3t2 - 6t +3
A) Find the anti-derivative of the velocity function and
acceleration function in order to determine the position function.
To find the constant after integration use the fact that
s(0)=1.
B) Find when the particle is speeding up and slowing down.
C) Find the total distance from time 0 to time...

A particle that moves along a straight line has velocity
v(t)=4t^(2)e^(-t) meters per second after t seconds. How far will
it travel during the first t seconds?

A particle travels along a straight line with a velocity
v=(12−3t^2) m/s , where t is in seconds. When t = 1 s, the particle
is located 10 m to the left of the origin.
Determine the displacement from t = 0 to t = 7 s.
Determine the distance the particle travels during the time
period given in previous part.

The velocity of a particle moving along a line is a function of
time given by v(t)=81/(t2+9t+18). Find the
distance
that the particle has traveled after t=9 seconds if it started at
t=0 seconds.

A particle moves along one dimension with a constant
acceleration of 4.60 m/s2 over a time interval. At the end of this
interval it has reached a velocity of 13.8 m/s.
(a)
If its original velocity is 6.90 m/s, what is its displacement
(in m) during the time interval?
m
(b)
What is the distance it travels (in m) during this
interval?
m
(c)
A second particle moves in one dimension, also with a constant
acceleration of 4.60 m/s2 ,...

A particle is moving along a coordinate line with an
acceleration of a(t) = 3t m/sec2. If s(0) = 2 m and v(0) = 18
m/sec, find the position of the particle after 1 sec.

A particle moves along a line with velocity v(t)= t-ln(t^2+1).
What is the maximum velocity on the interval [0,2]?

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