The force required to maintain the spring at 0.5m is 40 N. And force required to maintain the spring at 0.45m is 25 N. How much work is necessary to move the spring from 0.6m to 1m.
Hooke's Law states that the force required to maintain a spring stretched x meters beyond its natural length is kx
Let the natural length of spring be L. Then we can write, for the force being experienced in both cases,
To solve, we divide (1) by (2)
Now we find the distance by which spring is moved beyond its natural state
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