Question

A toy racecar races along a circular track. The racecar starts at the 6-o'clock position and travels in the CCW direction, and is always 4.5 feet from the center of the race track. Imagine an angle with an initial ray pointing in the 6 o'clock direction and with a terminal ray passing through the racecar. (Draw a diagram of this!) Let θθ represent the angle's measure.

1. Write an expression (in terms of θθ) that represents the measure of the angle with an initial ray pointing in the 3 o'clock direction and with a terminal ray passing through the racecar.

     

2. Write a formula that expresses the car's horizontal distance to the right of the center of the race track in feet, hh, in terms of θθ.

   h=

3. If θ=2.8θ=2.8 radians then the car is how many feet to the right of the center of the race track?

   feet   

Answer 1

Solution - Let o be angle made by toy car P I' than angle 2 Expression for from P T made with OP I-a Horizontal distance is given by 4,5 Com (5+) +4.5 4.5 sin Ox 4,5 4.5 - 4.5 sino y or y y