Question

Solve the initial value problem y' = 3x^2 − 2y, y(0) = 4

Answer #1

Solve the initial value problem y = 3x^2 − 2y, y(0) = 4

solve the initial value problem: 2x-3e^(3x)y-e^(3x)y'=0
y(0)=2

Solve the initial value problem.
x'=x+2y
y'=7x+y
with inition contitions x(0)=2 and y(0)=4.

For the initial value problem
• Solve the initial value problem.
y' = 1/2−t+2y withy(0)=1

solve the initial value problem y''-2y'+5y=u(t-2) y(0)=0
y'(0)=0

Solve the following initial value problem.
y''-2y'+2y=4x+5. ; y(0)=3. and y'(0)=0

Solve the initial value problem.
d^2y/dx^2= -3 csc^2 x; y' (pi/4)=0; y(pi/2)=0
The solution is y=____.

Solve the Initial Value Problem:
?x′ = 2y−x
y′ = 5x−y
Initial Conditions:
x(0)=2
y(0)=1

Solve the initial value problem y''−y'−2y=0, y(0) = α, y'(0) =2.
Then ﬁnd α so that the solution approaches zero as t →∞

Solve the initial value problem. 5d^2y/dt^2 + 5dy/dt -
y = 0; y(0)=0, y'(0)=1

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