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Question 6. Find the distance from point P(1,−2,3) to the plane of equation (x−3) + 2(y...

Question 6. Find the distance from point P(1,−2,3) to the plane of equation (x−3) + 2(y + 1)−4z = 0.

Question 8. Consider the function f(x,y) = x|x|+|y|, show that fx(0,0) exists but fy(0,0) does not exist.

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Homework Answers

Answer #1

Question 6:

The equation of the given plane is (x−3) + 2(y + 1)−4z = 0.

x-3 +2y+2-4z=0

Combining the like terms:

x+2y-4z-1=0

The given point is:

The distance from a point to a plane ax+by+cz+d=0 is calculated using the formula:

So the distance from the given point to the given plane is:

I request you to submit your other question as a separate question so that we will definitely help you with that as well.

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