Question

Find the volume of the solid by subtracting two volumes, the solid enclosed by the parabolic cylinders

y = 1 − x^{2},

y = x^{2} − 1

and the planes

x + y + z = 2,

6x + 2y − z + 14 = 0.

Answer #1

Find the volume of the solid by subtracting two volumes, the
solid enclosed by the parabolic cylinders
y = 1 − x2,
y = x2 − 1
and the planes
x + y + z = 2,
5x + 5y − z + 20 = 0.

Please answer ASAP
Find the volume of the solid by subtracting two volumes, the
solid enclosed by the parabolic cylinders y = 1
- x 2, y = x
2 - 1 and the planes x + y +
z = 2, 4x + 3y - z + 18 =
0.

Find the integral that represents the volume of the solid
bounded by the planes y = 0, z = 0, y = x and 6x + 2y + 3z = 6
using double integrals.

Find the integral that represents the volume of the solid
bounded by the planes y = 0, z = 0, y = x, and 6x + 2y + 3z = 6. No
need to solve the integral.

Find the volume of the solid bounded by the parabolic cylinders
z= y^2+1 and z=2-x^2.
***Please make it easy for me to follow along, thanks!

Use a triple integral to find the volume of the given solid.
The tetrahedron enclosed by the coordinate planes and the
plane
11x + y + z = 2

find the double integral that represents the
volume of the solid entrapped by the planes y=0, z=0, y=x and
6x+2y+3z=6 (please explain how to get the limits of integration)
you don't need to solve the integral just leave it expressed

Find the integral that represents:
The volume of the solid under the cone z = sqrt(x^2 + y^2) and
over the ring 4 ≤ x^2 + y^2 ≤ 25
The volume of the solid under the plane 6x + 4y + z = 12 and
on the disk with boundary x2 + y2 = y.
The area of the smallest region, enclosed by the spiral rθ =
1, the circles r = 1 and r = 3 & the polar...

use a double integral in polar coordinates to find the volume of
the solid in the first octant enclosed by the ellipsoid
9x^2+9y^2+4z^2=36 and the planes x=sqrt3 y, x=0, z=0

find the volume of the solid enclosed by the two paraboloids
y=x^2+z^2 and y=2-x^2-z^2

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