A process control manager is considering two robots to improve materials-handling capacity in the production of rigid shaft couplings that make dissimilar drive components. Robot X has a first cost of $76,000, an annual M&O cost of $31,000, and $42,000 salvage value, and it will improve revenues by $96,000 per year. Robot Y has a first cost of $146,000, an annual M&O cost of $28,000, and $47,000 salvage value, and it will increase revenues by $121,000 per year. The company’s MARR is 46% per year, and it uses a 3-year study period for economic evaluations. Calculate the incremental ROR, and identify the robot the manager should select.
The incremental ROR is_____%.
The manager should select robot_____.
Incremental ROR : | |||||||
year | X - Cash flow | Y - Cash flow | difference | dis 9% | dis 10% | 9% PV of CF | 10% PV of CF |
0 | -76000 | -146000 | -70000 | 1 | 1 | ||
1 | 65000 | 93000 | 28000 | 0.917 | 0.909 | 25676 | 25452 |
2 | 65000 | 93000 | 28000 | 0.842 | 0.826 | 23576 | 23128 |
3 | 107000 | 140000 | 33000 | 0.772 | 0.751 | 25476 | 24783 |
Total | 74728 | 73363 | |||||
Incremental ROR = 9% + (74728 - 70000) / (74728 - 73363) * (10% - 9%) | |||||||
Incremental ROR = 9% + 3.46% = 12.46% | |||||||
The manager should select Robot Y, because the incremental ROR is in positive | |||||||
which means Robot Y is having a edge over Robot X. |
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