Question

Machine A costs \$30,000 to purchase and is worth \$9,000 in 5 years. Machine B costs...

Machine A costs \$30,000 to purchase and is worth \$9,000 in 5 years. Machine B costs \$15,000 to purchase and is worth \$2,000 in 2 years. Assume that these machines are needed for 20 years and can be repurchased at the same price in the future. (use 13% interest rate)

Compute the Annual Equivalent Cost of each machine and subtract those values. Record the difference as a POSITIVE if Machine A is best, or a NEGATIVE if Machine B is best.

 Machine A: AW of first cost = 30000*(0.13*1.13^5)/(1.13^5-1) = \$ 8,529.44 [The formula for finding PV of annuity is adapted and used] AW of Salvage value = 9000*0.13/(1.13^5-1) = \$ 1,388.83 AEC = 8529.44-1388.83 = \$ 7,140.61 Machine B: AW of first cost = 15000*(0.13*1.13^2)/(1.13^2-1) = \$ 8,992.25 AW of Salvage value = 2000*0.13/(1.13^2-1) = \$     938.97 AEC = 8992.25-938.97 = \$ 8,053.28 Difference in AEC = 7140.61-8053.28 = \$    -912.67 Machine A is best as its AEC is lowest

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