Question

A salesman normally makes a sale​ (closes) on

6060​%

of his presentations. Assuming the presentations are​ independent, find the probability of each of the following.​a) He fails to close for the first time on his

fifthfifth

attempt.​b) He closes his first presentation on his

fourthfourth

attempt.

​c) The first presentation he closes will be on his second attempt.

​d) The first presentation he closes will be on one of his first three attempts.

​a) The probability he fails to close for the first time on his

fifthfifth

attempt is

nothing.

​(Round to four decimal places as​ needed.)

Answer 1

Hello Sir/ Mam

Let A be the event that the salesman closes a presentation.

Hence, given that :

P(A) = 0.6

Now,

a) He fails to close for the first time on his fifth attempt:

​

b) He closes his first presentation on his fourth attempt:

c) The first presentation he closes will be on his second attempt.

(d) The first presentation he closes will be on one of his first three attempts.

I hope this solves your doubt.

Do give a thumbs up if you find this helpful.