Suppose that your firm is trying to decide between two machines that will do the same job. Machine A costs $50,000, will last for ten years and will require operating costs of $5,000 per year. At the end of ten years it will be scrapped for $10,000. Machine B costs $60,000, will last for seven years and will require operating costs of $6,000 per year. At the end of seven years it will be scrapped for $5,000. Which is a better machine and why? (discount rate is 10 percent) | |||||||||||||||||
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Machine A | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Initial Invetsment | -50000 | ||||||||||
Operating Costs | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | |
Scrape Value | 10000 | ||||||||||
Total Cash Flow | -50000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | -5000 | 5000 |
NPV = | -76867.40 | ||||||||||
Equivalent Annual
Cost = r * NPV/[(1 -(1+r)^-n] |
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-12509.82 | |||||||||||
Machinne B | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | |||
Initial Invetsment | -60000 | ||||||||||
Operating Costs | -6000 | -6000 | -6000 | -6000 | -6000 | -6000 | -6000 | ||||
Scrape Value | 5000 | ||||||||||
Total Cash Flow | -60000 | -6000 | -6000 | -6000 | -6000 | -6000 | -6000 | -1000 | |||
NPV = | -86644.72 | ||||||||||
Equivalent Annual
Cost = r * NPV/[(1 -(1+r)^-n] |
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-17797.30248 |
B. A is a better machine because it has a smaller Equivalent Annual Cost.
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