Question

How do you solve for If Machine A has a NPW of $29,282 and Machine B...

How do you solve for

If Machine A has a NPW of $29,282 and Machine B has a NPW of $40,847 over an 8-year period, what is the difference in the annual worth of Machine B over Machine A at a rate of 10% p. y. c. y?

Right answer:

$2,168

Answers:

$1,579

$1,789

$2,168

$2,328

Homework Answers

Answer #1

$2,168

Working:

a. Present Value of annuity of 1 = (1-(1+i)^-n)/i Where,
= (1-(1+0.10)^-8)/0.10 i 10%
= 5.3349262 n 8
b. Difference in NPW = $       40,847 - $       29,282
= $       11,565
c. Difference in annual worth = $       11,565 / 5.3349262
= $         2,168
Note:
NPW is the present value of annual worth.
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
If Machine A has a NPW of $29,282 and Machine B has a NPW of $40,847...
If Machine A has a NPW of $29,282 and Machine B has a NPW of $40,847 over an 8-year period, what is the difference in the annual worth of Machine B over Machine A at a rate of 2% p. y. c. y? $1,304 $592 $804 $1,579
How do you solve for Find the value of P for which the inflows will equal...
How do you solve for Find the value of P for which the inflows will equal the outflows. Find the effective rate first. Rate 21% p y c d Year Outflows Inflows 0 -P 1 -2P 2 -4P 3 -8P 4 -16P 5 $24,000 6 $30,000 7 $36,000 8 $42,000 9 $48,000 10 $54,000 Right Answer: $2,856
Machine X has an initial cost of $12,000 and annual maintenance of $700 per year. It...
Machine X has an initial cost of $12,000 and annual maintenance of $700 per year. It has a useful life of four years and no salvage value at the end of that time. Machine Y costs $22,000 initially and has no maintenance costs during the first year. Maintenance is $200 at the end of the second year and increases by $200 per year thereafter. Machine Y has a useful life of eight years and an anticipated salvage value of $5,000...
A company wants to buy one of two machines: machine X or machine Y. The present...
A company wants to buy one of two machines: machine X or machine Y. The present worth of machine X over a life span of 3 years is $2,200 at an interest rate of 10% per year compounded annually whereas the present worth of machine Y over a life span of 6 years is $ 3,500 at the same interest rate. Based on the present worth criterion, which machine should the company pick? PLEASE HELP ASAP. dont use excel. solve...
How do you solve - What is the present value of $2,100 a year at a...
How do you solve - What is the present value of $2,100 a year at a discount rate of 8% if the first payment is received 7 years from now and you receive a total of 23 annual payments? - using a financial calculator?
PLEASE SOLVE NOT USING EXCEL OR A TABLE A machine costs $750,000 to purchase and will...
PLEASE SOLVE NOT USING EXCEL OR A TABLE A machine costs $750,000 to purchase and will produce $250,000 per year revenue. Annual operating and maintenance cost is $70,000. The machine will have to be upgraded in year 4 at a cost of $150,000. The company plans to use the machine for 8 years and then sell it for scrap for which it expects to receive $30,000. The company MARR interest rate is 10%. Compute the net present worth to determine...
A company is looking to purchase a machine based on two options Machine A Machine B...
A company is looking to purchase a machine based on two options Machine A Machine B Initial cost AED 60,000 90,000 Annual cost/year AED 10,000 4,000 Salvage Value AED 4,000 0 Useful life in years 3 3 Using an interest rate of 12%, answer the below questions.       -       A.       B.       C.       D.       E.       F.       G.       H.       I.       J....
A company buys a machine for $25,000. The annual cost of maintaining the machine is $500...
A company buys a machine for $25,000. The annual cost of maintaining the machine is $500 per year for the first 5 years (End of Year 1 thru End of Year 5) and then it increases to $750 for the next 5 years (Year 6 thru Year 10). Consider all cash flows to be end of year cash flows. For an interest rate of 8% per year compounded yearly, find the annual maintenance cost of the machine and the present...
how do you solve (A/P, 6%, 7) what are you supposed to do to get the...
how do you solve (A/P, 6%, 7) what are you supposed to do to get the total inside the parentheses? how do you solve for A/P? and what does it mean?
A certain machine has the estimates shown below: Machine First Cost ($) -20,000 Annual operating cost...
A certain machine has the estimates shown below: Machine First Cost ($) -20,000 Annual operating cost ($/ year) -10,000 Salvage value ($) 4,000 Life (years) 10 At an interest rate of 10% per year, the annual worth of this machine is equal to: Question 10 options: -$13,004 -$13,254 -$12,658 -$15,270
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT