Please show the work
TR = 1,000Q – 0.1Q2
The company has estimated a functional relationship between total output produced and the total cost. The annual cost of producing racquet balls in dollars is:
TC = 40,000 - 200Q + 0.4Q2
(a) Profit is miximized where Marginal revenue is equal to Marginal cost.
First we will calculate the marginal revenue and marginal cost by differentiation as per below:
Marginal revenue (dTR/ dQ) = 1000 - 0.2Q
Marginal cost (dTC / dQ) = -200 + 0.8Q
Now, we will equate MR and MC as per below:
1000 - 0.2Q = -200 + 0.8Q
1000 + 200 = 0.8Q + 0.2Q
1200 = Q
So, profit maximizing output is 1200 units.
(b) Profit is given by:
Profit = Total revenue (TR) - Total cost (TC)
Profit = 1000 Q- 0.1Q2 - 40000 + 200Q - 0.4Q2
Profit = -40000 + 1200 Q - 0.5Q2
Now, for maximum profit, we will put the value of Q = 1200 in the above equation as below,
Profit = -40000 + 1200 (1200) - 0.5 (1200)2
Profit = - 40000 + 1440000 - 720000
Profit = 680000
So, maximum profit = 680000
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