A borrower obtains a fully amortizing constant payment mortgage loan for $75,000 at 12 percent for 3 years. Payments are monthly. What will be the amount of remaining balance at the end of the second month? (Answer is rounded)
The formula to find the monthly payment=loan amount*interest rate*(1+interest rate)^n/[((1+interest rate)^n)-1]
interest rate=monthly interest rate=12%/12=1%
n=total number of periods=3*12=36
monthly payment=75000*1%*(1+1%)^36/[((1+1%)^36)-1]
=75000*1%*1.430769/0.430769
=2491.1
The formulas and outstanding balance after 2nd montly payment is given below.
The end of the second month outstanding=$71,500.4
Periods | Opening balance | Monthly payment | Interest=(Opening balance*(12%/12)) | Principal=monthly payment-Interest | Ending balance=Opening balance-principal |
1 | 75000.0 | 2491.1 | 750.0 | 1741.1 | 73258.9 |
2 | 73258.9 | 2491.1 | 732.6 | 1758.5 | 71500.4 |
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