Management wants to change the safety stock of dehydrated water
to be 1.75 pounds. This item has a standard deviation during the
lead time of 1.5 pounds with an average of 59.9 pounds maintained
in inventory.
Calculate the percentage of time that you expect to run out of
dehydrated water. (Keep two decimal places in your answer that
represents percentage)
Solution:
Given that Safety Stock, = 1.75, Lead time, = 1 and Standard deviation, = 1.5
We know that
1.75 =
= 1.1667
By using normsdist(1.1667) we get percentage of time that you expect not to run out of dehydrated water
percentage of time that you expect not to run out of dehydrated water = 0.8783 = 87.83%
percentage of time that you expect to run out of dehydrated water = 1- percentage of time that you expect not to run out of dehydrated water = 1-0.8783 = 0.1217 =12.17%
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