A bank recently loaned you $14,015.00 to buy a car. The loan is for 4 years in is fully amortized. The nominal rate on the loan is 11%, and payments are made at the end of each month. What will be the remaining balance on the loan after you make payment number 25?
Step 1 : | EMI = [P x R x (1+R)^N]/[(1+R)^N-1] | ||||
Where, | |||||
EMI= Equal Monthly Payment | |||||
P= Loan Amount | |||||
R= Interest rate per period =11%/12 =0.9166667% | |||||
N= Number of periods =12*4 =48 | |||||
= [ $14015x0.0091666667 x (1+0.0091666667)^48]/[(1+0.0091666667)^48 -1] | |||||
= [ $128.4708338005( 1.0091666667 )^48] / [(1.0091666667 )^48 -1 | |||||
=$362.2249 | |||||
Step 2 : | Calcualtion of loan amount after 25th payment | ||||
Present Value Of An Annuity | |||||
= C*[1-(1+i)^-n]/i] | |||||
Where, | |||||
C= Cash Flow per period | |||||
i = interest rate per period =11% /12 =0.916667% | |||||
n=number of period =48-25 =23 | |||||
= $362.2249[ 1-(1+0.009166667)^-23 /0.009166667] | |||||
= $362.2249[ 1-(1.009166667)^-23 /0.009166667] | |||||
= $362.2249[ (0.1893) ] /0.009166667 | |||||
= $7,480.78 | |||||
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