A car loan in the amount of $32,000 will be repaid over a five year term. The rate on the loan is 6%, and payments are compounded monthly. Determine the balance on the loan at the end of month 3.
EMI = P*i*[(1+i)^n]/[{(1+i)^n}-1]
Where,
P = Principal = 32000
i = Interest Rate = 0.06/12 = 0.005
n = Number of periods = 5*12 = 60
Therefore, EMI = 32000*0.005*[(1+0.005)^60]/[{(1+0.005)^60}-1]
= 160*(1.34885)/[1.34885-1] = $618.65
Amortization Schedule:
Period | Opening Principal (previous closing) |
Interest (opening*0.005) |
Installment | Principal Repayment (installment-interest) |
Closing Principal (opening-principal repayment) |
1 | 32000 | 160 | 618.65 | 458.65 | 31541.35 |
2 | 31541.35 | 157.70675 | 618.65 | 460.94325 | 31080.40675 |
3 | 31080.40675 | 155.4020338 | 618.65 | 463.2479663 | 30617.15878 |
Therefore, Balance at the end of 3rd month = $30617.16
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