Question

a sample of the personnel files of 8 male employees revealed that during a 6 month...

a sample of the personnel files of 8 male employees revealed that during a 6 month period they lost the following number of days to illness: 2, 0,6,3,10,4,1,2. What is the mean devistion is days?

Homework Answers

Answer #1

For calculation of Mean deviation ,

Employee

A

No of days lost

B

Deviation from mean

C=B-M(mean or average)

absolute deviation

Ignore signs (+or -)

1 2 2-28/8=-12/8 12/8
2 0 0-28/8=-28/8 28/8
3 6 6-28/8=20/8 20/8
4 3 3-28/8=-4/8 4/8
5 10 10-28/8=52/8 52/8
6 4 4-28/8=4/8 4/8
7 1 1-28/8=-20/8 20/8
8 2 2-28/8=-12/8 12/8
Total 28 152/8

Mean =28/8

Step-1

first need to calculate Mean (Average)=Sum of the lost days/Number of employees

=2+0+6+3+10+4+1+2/8

=28/8

step-2

calculate sum of absolute deviation =152

step-3

Mean deviation =sum of absolute deviation/No of date values (here No.of employees)

=152/8

=19 days

formula for mean deviation=

X=Data value

=Mean

N=Number of data values

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