a sample of the personnel files of 8 male employees revealed that during a 6 month period they lost the following number of days to illness: 2, 0,6,3,10,4,1,2. What is the mean devistion is days?
For calculation of Mean deviation ,
Employee A |
No of days lost B |
Deviation from mean C=B-M(mean or average) |
absolute deviation Ignore signs (+or -) |
1 | 2 | 2-28/8=-12/8 | 12/8 |
2 | 0 | 0-28/8=-28/8 | 28/8 |
3 | 6 | 6-28/8=20/8 | 20/8 |
4 | 3 | 3-28/8=-4/8 | 4/8 |
5 | 10 | 10-28/8=52/8 | 52/8 |
6 | 4 | 4-28/8=4/8 | 4/8 |
7 | 1 | 1-28/8=-20/8 | 20/8 |
8 | 2 | 2-28/8=-12/8 | 12/8 |
Total | 28 | 152/8 |
Mean =28/8
Step-1
first need to calculate Mean (Average)=Sum of the lost days/Number of employees
=2+0+6+3+10+4+1+2/8
=28/8
step-2
calculate sum of absolute deviation =152
step-3
Mean deviation =sum of absolute deviation/No of date values (here No.of employees)
=152/8
=19 days
formula for mean deviation=
X=Data value
=Mean
N=Number of data values
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