X Company is considering replacing one of its machines in order
to save operating costs. Operating costs with the current machine
are $65,000 per year; operating costs with the new machine are
expected to be $33,530 per year. The new machine will cost $154,000
and will last for five years, at which time it can be sold for
$3,000. The current machine will also last for five more years but
will not be worth anything at that time. It cost $40,000 four years
ago, but its current disposal value is only $4,000.
9. Assuming a discount rate of 7%, what is the incremental net
present value of replacing the current machine?
10. Assume the following two changes: 1) both machines will last
for six more years, 2) the salvage value of the new machine after
six years will be zero. If X Company replaces the current
equipment, what is the approximate internal rate of return?
Present Value of $1.00
Period | 3% | 4% | 5% | 6% | 7% | 8% | 9% | 10% | 11% | 12% |
---|---|---|---|---|---|---|---|---|---|---|
1 | 0.971 | 0.962 | 0.952 | 0.943 | 0.935 | 0.926 | 0.917 | 0.909 | 0.901 | 0.893 |
2 | 0.943 | 0.925 | 0.907 | 0.890 | 0.873 | 0.857 | 0.842 | 0.826 | 0.812 | 0.797 |
3 | 0.915 | 0.889 | 0.864 | 0.840 | 0.816 | 0.794 | 0.772 | 0.751 | 0.731 | 0.712 |
4 | 0.888 | 0.855 | 0.823 | 0.792 | 0.763 | 0.735 | 0.708 | 0.683 | 0.659 | 0.636 |
5 | 0.863 | 0.822 | 0.784 | 0.747 | 0.713 | 0.681 | 0.650 | 0.621 | 0.593 | 0.567 |
6 | 0.837 | 0.790 | 0.746 | 0.705 | 0.666 | 0.630 | 0.596 | 0.564 | 0.535 | 0.507 |
7 | 0.813 | 0.760 | 0.711 | 0.665 | 0.623 | 0.583 | 0.547 | 0.513 | 0.482 | 0.452 |
8 | 0.789 | 0.731 | 0.677 | 0.627 | 0.582 | 0.540 | 0.502 | 0.467 | 0.434 | 0.404 |
Present Value of an Annuity of $1.00
Period | 3% | 4% | 5% | 6% | 7% | 8% | 9% | 10% | 11% | 12% |
---|---|---|---|---|---|---|---|---|---|---|
1 | 0.971 | 0.962 | 0.952 | 0.943 | 0.935 | 0.926 | 0.917 | 0.909 | 0.901 | 0.893 |
2 | 1.913 | 1.886 | 1.859 | 1.833 | 1.808 | 1.783 | 1.759 | 1.736 | 1.713 | 1.690 |
3 | 2.829 | 2.775 | 2.723 | 2.673 | 2.624 | 2.577 | 2.531 | 2.487 | 2.444 | 2.402 |
4 | 3.717 | 3.630 | 3.546 | 3.465 | 3.387 | 3.312 | 3.240 | 3.170 | 3.102 | 3.037 |
5 | 4.580 | 4.452 | 4.329 | 4.212 | 4.100 | 3.993 | 3.890 | 3.791 | 3.696 | 3.605 |
6 | 5.417 | 5.242 | 5.076 | 4.917 | 4.767 | 4.623 | 4.486 | 4.355 | 4.231 | 4.111 |
7 | 6.230 | 6.002 | 5.786 | 5.582 | 5.389 | 5.206 | 5.033 | 4.868 | 4.712 | 4.564 |
8 | 7.020 | 6.733 | 6.463 | 6.210 | 5.971 | 5.747 | 5.535 | 5.335 | 5.146 | 4.968 |
Years | 0 | 1 - 5 | 5 | ||
Cost of new machine | -154000 | ||||
Sale of old machine | 4000 | ||||
Savings in operating cost(65000-33530) | 31470 | ||||
Salvage of new machine | 3000 | ||||
NCF | -150000 | 31470 | 3000 | ||
PV Factor @ 7% | 1 | 4.100 | 0.7130 | ||
PV of NCF | -150000 | 129033 | 2139 | ||
Incremental NPV = | -18828 | ||||
IRR is the rate at which the NPV =0 | |||||
New cashflows | |||||
Years | 0 | 1 - 6 | |||
Cost of new machine | -154000 | ||||
Sale of old machine | 4000 | ||||
Savings in operating cost(65000-33530) | 31470 | ||||
NCF | -150000 | 31470 | |||
PV of Inflow = PV of outflow | |||||
PVAF(r,6) x 31470 = | 150000 | ||||
PVAF(r,6) = | 150000/31470 | ||||
4.766 | |||||
From annuity table - | |||||
PVAF(r,6) = | 4.766 | ||||
r = | 7% | ||||
(Check in annuity table annuity factor for 6 years ) | |||||
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