(Hit: Deposit a one time lump sum into an investment account and let it sit for 32 years.)
i) Assuming that the investment account earned 9.8% interest, compounded monthly, how much would John have to deposit at the start to reach his goal?
ii) Suppose that John had only $6000 to invest at the beginning, how old would John be when that investment reaches $1,000,000?
iii) Suppose again that John had only $6,000 to invest at the beginning, what interest rate would be required to meet his goal at age 50?
Note: please turn in all the exercises the following (step by step).
i).
Let x be the deposit which John will deposit. After 32 years, For the final amount to be 1000000, the monthly compounding formula will be x*(1+r/12)^(12*32)= x*(1+r/12)^384. So, 1000000= x*(1+9.8%/12)^384. On solving, x is 44013.28
So, John has to deposit $44013.28 at the start to reach his goal.
ii).
Let n be the time period after which the investment will be 1000000. Using the same forma, 1000000= 6000*(1+9.8%/12)^n. On solving, n will be 629 months which is 52.42 Years.
So, John will be 70.42 Years old when his investment reaches $1000000.
iii).
Let r be the interest rate. Using the same formula, we have 1000000= 6000*(1+r/12)^384. On solving, we get r is 16.09%.
So, interest rate need to be 16.09%.
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