An industrial bank will loan you $20,500 for three years to buy miscellaneous equipment for your firm. The loan must be repaid in equal monthly payments. The annual interest rate on the loan is 8.5% of the unpaid balance. How large are the monthly payments?
Given,
Loan amount = $20500
Annual interest rate = 8.5% or 0.085
Number of years = 3 years
Solution :-
Monthly interest rate (r) = 0.085/12 = 0.00708333333
Number of months (n) = 3 years x 12 = 36
Now,
Monthly payment = (Loan amount x r) [1 - (1 + r)-n]
= ($20500 x 0.00708333333) [1 - (1 + 0.00708333333)-36]
= $145.208333265 [1 - (1.00708333333)-36]
= $145.208333265 [1 - 0.77561337029952]
= $145.208333265 0.22438662970048 = $647.13
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