Directions: Consider the following case and share your response to the following five questions with your instructor
Case: A borrower received a 30-year ARM mortgage loan for $200,000. Rate caps are 3/2/6. The start rate is 3.50% and the loan adjusts every 12 months for the life of the mortgage. The index used for this mortgage is LIBOR (for this exercise, 3.00% at the start of the loan, 4.45% at the end of the first year, and 4.50% at the end of the second year). The margin on the loan is 3.00%, which remains the same for the duration of the loan.
Initial start rate for the first year=3.50% (as given in the problem)
Interest rate the borrower will pay after the first rate adjustment= 6.5%
Being lower of the following two:
(a ): 3.50% (start rate) + 3% (Cap for the first year) = 6.5%
(b ): 4.45% (Index-LIBOR) + 3% (Margin) = 7.75%
Fully indexed rate after the second year = Index (LIBOR at the end of first year) + Margin
=4.50% + 3% = 7.50%
Maximum interest rate the borrower will pay during the 30-year term for this loan
= Start rate + Life time loan cap = 3.50% + 6% = 9.50%
Index (LIBOR) in the event of the loan reaching the maximum interest rate=
Maximum rate as above – Margin= 9.50%-3% = 6.50%
Get Answers For Free
Most questions answered within 1 hours.