Question

What is the standard deviation of 26%, 15%, -14%,-15%, 2%, -18%, 42%, 30%, -32% and 28%

What is the standard deviation of 26%, 15%, -14%,-15%, 2%, -18%, 42%, 30%, -32% and 28%

Homework Answers

Answer #1

Average Return = [0.26 + 0.15 + (-0.14) + (-0.15) + 0.02 + (-0.18) + 0.42 + 0.30 + (-0.32) + 0.28] / 10
Average Return = 0.64 / 10
Average Return = 0.0640 or 6.40%

Variance = [(0.26 - 0.064)^2 + (0.15 - 0.064)^2 + (-0.14 - 0.064)^2 + (-0.15 - 0.064)^2 + (0.02 - 0.064)^2 + (-0.18 - 0.064)^2 + (0.42 - 0.064)^2 + (0.30 - 0.064)^2 + (-0.32 - 0.064)^2 + (0.28 - 0.064)^2] / 9
Variance = 0.57124 / 9
Variance = 0.063471

Standard Deviation = (0.063471)^(1/2)
Standard Deviation = 0.2519 or 25.19%

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider the following sample data: 6, 12, 20,8, 14, 18, 42, 28. What is the standard...
Consider the following sample data: 6, 12, 20,8, 14, 18, 42, 28. What is the standard deviation?
29 26 26 42 53 28 47 67 49 32 26 27 20 27 27 27...
29 26 26 42 53 28 47 67 49 32 26 27 20 27 27 27 27 32 36 27 33 49 21 26 42 Create Standard Deviation Chart (Normal Distribution Curve)
what is the sample standard deviation of data set 15, 18, 16, 18, 15,13, 14, 18,...
what is the sample standard deviation of data set 15, 18, 16, 18, 15,13, 14, 18, 16, 10?
39 29 20 33 28 25 23 34 37 39 26 34 33 42 32 42...
39 29 20 33 28 25 23 34 37 39 26 34 33 42 32 42 45 24 32 41 48 36 16 13 40 A survey of 25 randomly selected customers found the ages shown​ (in years). The mean is 32.44 years and the standard deviation is 8.97 years. ​a) Construct a 99​% confidence interval for the mean age of all​ customers, assuming that the assumptions and conditions for the confidence interval have been met. ​b) How large is...
Consider the population below. 36 18 19 15 26 36 27 28 25 37 14 27...
Consider the population below. 36 18 19 15 26 36 27 28 25 37 14 27 14 26 14 The sample below was drawn from this population. Complete parts a and b below. 26 36 14 25 14 27 18 14. a. Compute the sampling error for the sample mean in this situation. The sampling error for the sample mean is____​(Round to two decimal places as​ needed.) b. Determine the largest possible sampling error for this sample of equals=8. The...
1. 30 53 12 42 29 51 25 26 45 18 32 10 31 6 a....
1. 30 53 12 42 29 51 25 26 45 18 32 10 31 6 a. Construct a frequency distribution. use the following class intervals: 0-9, 10-19, 20-29, 30-39, 40-49, 50-59. b. construct a steam-and leaf plot. C. construct a histogram. use class boundaries along the x-axis.
For the following Simple data ( separately ) : 18 , 30 , 14 , 21...
For the following Simple data ( separately ) : 18 , 30 , 14 , 21 , 25 , 24 , 34 , 15 , 25 , 26 , 18 , 24 , 18 , 33 , 20 1) Find ( Mean , Mode , Median , Range , Midrange , Standard Deviation , Variance )
Given the data below: 14 18 30 30 31 31 32 32 33 33 34 36...
Given the data below: 14 18 30 30 31 31 32 32 33 33 34 36 38 39 40 41 41 42 42 43 43 43 44 44 45 45 46 46 47 47 47 65 70 A. Make frequency diagram with 6 classes B. Draw Histogram C. Give 5 number summary D. Draw the box and whicker diagram showing the fences, the whiskers, and the outliers
Given the sample data. x: 18 15 26 30 14 (a) Find the range. (b) Verify...
Given the sample data. x: 18 15 26 30 14 (a) Find the range. (b) Verify that Σx = 103 and Σx2 = 2321. Σx Σx2 (c) Use the results of part (b) and appropriate computation formulas to compute the sample variance s2 and sample standard deviation s. (Enter your answers to one decimal place.) s2 s (d) Use the defining formulas to compute the sample variance s2 and sample standard deviation s. (Enter your answers to one decimal place.)...
32, 34, 39, 40, 40, 42, 45, 50, 52, 68, 12, 13, 18, 20, 22, 24,...
32, 34, 39, 40, 40, 42, 45, 50, 52, 68, 12, 13, 18, 20, 22, 24, 26, 26, 28, 32 create a box and whisker plot for the data.