Question

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the...

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos(600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V.
The CMRR is _____dB?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the...
In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos(600t - 45◦) mV. The output is vo = 3cos (600t - 45◦) + 4.004cos (600t - 45◦) V. The CMRR is ______dB?
In a differential amplifier, the noninverting input is 3 cos (600t + 45◦ ) mV and...
In a differential amplifier, the noninverting input is 3 cos (600t + 45◦ ) mV and the inverting input is 4cos (600t - 45◦ ) mV. The output is vo = 3cos (600t + 45◦ ) + 4.004cos (600t - 45◦ ) V. The CMRR is _____________ dB.
In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input...
In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input is 4cos (600t - 45°) mV. The output is vo = 3cos (600t + 45°) + 4.004cos (600t - 45°) V. The CMRR is of? The unit must be in dB.
In a differential amplifier, the non-inverting input is 3 cos (600t - 45 ° ) mV...
In a differential amplifier, the non-inverting input is 3 cos (600t - 45 ° ) mV and the inverse input is 4cos (600t - 45◦ ) mV. The output is vo = 3cos (600t - 45◦ ) + 4.004cos (600t - 45◦ ) V. The CMRR is _______ dB.
In a differential amplifier, the non-inverting input is 3cos (600t + 45◦) mV and the inverting...
In a differential amplifier, the non-inverting input is 3cos (600t + 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦ ) + 4.004cos (600t - 45◦ ) V. The CMRR is _____dB.
Numeric responses must be either an integer (if exact) or a real number with three decimal...
Numeric responses must be either an integer (if exact) or a real number with three decimal places, with the least significant number rounded. Do not use commas. If there are units, the integer part must be between 1 and 999. Use the following units: Ohm, kOhm, mOhm resistors, etc. Conductances: S, mS, MS, etc. Voltage: V, kV, mV, MV, etc. Current: A, mA, kA, uA, nA, etc. Power: W, mW, kW, uA, pW, etc. Time: s, hrs, ks, ms, etc....
1. Design an inverting amplifier with gain of ×10, and input impedance of 100Ω. 2. Design...
1. Design an inverting amplifier with gain of ×10, and input impedance of 100Ω. 2. Design a non-inverting amplifier with a gain of ×10. Design the amplifier so that the output current from the op-amp at maximum output voltage +15V is no larger than 15 mA. 3. Design a current summing amplifier that finds the algebraic sum of two input voltages: VOUT = - (V1 + V2) . Design the amplifier so that output current from the op-amp at maximum...
1. Calculate the input difference in potential (eNI − eINV) for an op amp amplifier with...
1. Calculate the input difference in potential (eNI − eINV) for an op amp amplifier with an output voltage of 10 V and an open loop gain of a. 2000 b. 30,000 2. Locate specifications for the LM741 and the LF411 (National Semiconductor). For each determine the worst case a. input impedance. b. open loop gain c. gain bandwidth. 3. Assuming β = 0.05, and AOL = 2000, calculate the closed loop gain using the approximation.
-------Electronics 2------- 1. Design an amplifier using a MOSFET transistor (2N7000) with a Common Source (CS)...
-------Electronics 2------- 1. Design an amplifier using a MOSFET transistor (2N7000) with a Common Source (CS) configuration with a resistor in the Source. Its design should provide an amplification of -12V / V. 2. The voltage Vcc will be +8 vDC, the AC voltage will be 10 mV peak 5 kHz and the load resistance will be RL 2.2 kn. 3. Simulate the circuit in LTSpice. It must choose resistors Ro, Rs, RG1 and RG2 such that the circuit operates...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT