Question

The resistance of a semiconductor nanowire is R=12.93 k? for wire lengths up to 100nm and...

The resistance of a semiconductor nanowire is R=12.93 k? for wire lengths up to 100nm and increases by dR/dL = 3?/nm for wire lengths exceeding 100nm, measured at room temperature. If the effective electron mass is m*= 0.2 m0, what is the number of electrons per unit length in this nanowire?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The resistance of a metal wire with diameter of 200μm and length of 1.00m is 0.55Ω...
The resistance of a metal wire with diameter of 200μm and length of 1.00m is 0.55Ω . the density of conduction electrons in the metal is 8.50 x 1028 m-3. Assuming that the effective electron mass is me = 9.1 x 10-31kg, calculate i) the conductivity of the metal ii) the drude scattering time iii)the electron mobility (give the answer in units of cm2V-1s-1 iv) the fermi velocity of electrons.
1. Compute the resistivity of an intrinsic semiconductor at 300 K, in units of Ω-m, given...
1. Compute the resistivity of an intrinsic semiconductor at 300 K, in units of Ω-m, given that it has an intrinsic carrier concentration of 4.9 x1022m-3 and electron and hole mobilities of 0.53 and 0.09 m2/V-s, respectively. 2. The intrinsic concentration of electrons and holes (i.e. concentration of e-h pairs) in Si at room temperature is approximately 1x1010 cm-3. Given the density and atomic mass of Si to be 2.33 g/cm3 and 28.06 g/mol, determine the ratio of ionized to...
Aluminum wires exposed to air form a layer of insulating Al2O3, through which electrons have to...
Aluminum wires exposed to air form a layer of insulating Al2O3, through which electrons have to tunnel to get through an interconnect. A simple model of electrons tunneling through an Al2O3 barrier of thickness L between two Al wires implies the following: for small fixed voltage V, the current I is Ce^(-2KL), where C and K are constants. In other words, the resistance R=V/I increases proportional to e^(2KL). Solving the Schrödinger equation gives K=sqrt(2mU/ 2 ) where m is the...
What is the change in length of a metal rod with an original length of 4...
What is the change in length of a metal rod with an original length of 4 m, a coefficient of thermal expansion of 0.00002/ ° C, and a temperature change of 30° C? 1. 2.4 mm 2. 12 mm 3. 1.2 mm 4. 24 mm Determine the number of electrons passing through a point in the wire in 8 minutes when the current is 10 A. a. 3 * 1016 electrons b. none of these c. 4,800 electrons d. 1.6...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT