Question

% The current through a capacitor, i, is equal to the capacitor value
% multiplied by the rate of change of the voltage across it vs. t as it is
% charging, meaning i = C*dV/dt. If C = 1000e-6, and the voltage across the
% capacitor is measured every 0.5ms, shown in the table below,
% Find the current through the capacitor. Plot current (i) and voltage(V)
% on two different figures. How are the plots related?
%_______________________________________
% Time (ms) Voltage (V)
% 0 0
% 0.5 0.4
% 1 0.62
% 1.5 0.78
% 2 0.83
% 2.5 0.9
% 3 0.92
% 3.5 0.94
% 4 0.98
% 4.5 0.99
% 5 1

Answer 1

code:

result:

if capacitor connected to any dc source than in steady state capacitor will be open circuited means voltage will increase and current will decrease exponentially