Question

%% Simple Matlab Exercise:

A = ([ 1 0 0 1 ]);

B = ([ 0 0 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 0 ]);

C = ([ 0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0 ]);

% A is hidden within B and C as multiples of its bits with long pauses (many zeros) at the % beginning and end of the vectors

% Develop a matlab program by which A can be recovered from B or C

Answer 1

Ans)

There are many ways you can get 'A' from B or C,as there is no proper logic given how vector 'B' and 'C' is formed from vector 'A', I am writing simple matlab code for the above question because we know both inputs and outputs

%============MATLAB Code============%

B=([0 0 0 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 0]);

C=([0 0 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 0 0 0]);

A=[B(7) B(9) B(11) B(13)] % this line recovers vector A from B

A=[C(9) C(12) C(15) C(18)] % this line recovers vector A from C

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Output when you run the above code

=========

>>

A =

   1   0   0   1

A =

   1   0   0   1