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A technique is 300 mA and 200 ms using a 6:1 grid and produces an intensity...

A technique is 300 mA and 200 ms using a 6:1 grid and produces an intensity of 200 mR. What should the new intensity be (mR) if the current & time are kept constant and a 16:1 grid is substituted?

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Answer #1

So basically we will use inverse squre law between intensities and SID to get the relation between Intensity1 and Intensity2. So the inverse square law is : (Intensity1/Intensity2) = (SID2/SID1)2

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