Question

A technique is 300 mA and 200 ms using a 6:1 grid and produces an intensity...

A technique is 300 mA and 200 ms using a 6:1 grid and produces an intensity of 200 mR. What should the new intensity be (mR) if the current & time are kept constant and a 16:1 grid is substituted?

Engineering   Electrical-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

So basically we will use inverse squre law between intensities and SID to get the relation between Intensity1 and Intensity2. So the inverse square law is : (Intensity1/Intensity2) = (SID2/SID1)2

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A technique of 20 mA, 400 ms produces an intensity of 200 mR. If the current...
A technique of 20 mA, 400 ms produces an intensity of 200 mR. If the current is doubled and the intensity is to be held constant find the new time
A good radiograph is taken with 100 mA, 240 ms, 150 RS, 200 cm SID and...
A good radiograph is taken with 100 mA, 240 ms, 150 RS, 200 cm SID and a 5:1 grid. If mA is kept constant what time will be used if a technique of: 75 RS, 100 cm SID and a 10:1 grid is substituted? A radiograph has an intensity of 360 mR at a distance of 80 inches what will the intensity be at 120 inches? A good exposure is taken using 60 mAs and then the radiographer increases the...
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm...
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm OID, 1mm FSS, 8:1 grid, 400 IP (CR), and no pathological condition. In order to maintain the Detective Quantum Efficiency (DQE) of the image, what would be the new exposure factor at 91 cm?
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm...
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm OID, 1mm FSS, 8:1 grid, 400 IP (CR), and no pathological condition. 4. In order to maintain the Detective Quantum Efficiency (DQE) of the image, what would be the new exposure factor at 91 cm? (2 points)
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm...
A satisfactory radiographic image was obtained using 300 mA, 20ms at 90 kVp, 182cm SID, 20cm OID, 1mm FSS, 8:1 grid, 400 IP (CR), and no pathological condition. 6. To reduce exposure to the patient, is the imaging plate (IP) and kVp used for this procedure acceptable? Please explain your answer and rationale. (2 points)
Period Forecast 1 200 2 500 3 300 4 400 5 200 6 200 Regular time:...
Period Forecast 1 200 2 500 3 300 4 400 5 200 6 200 Regular time: $20 per unit (maximum of 280 units per period) Overtime:    $30 per unit (maximum of 40 units per period) Subcontracting:    Not available Beginning inventory:   None Carrying cost: $10 per unit per period Backorder cost: $50 per unit per period What is the first period in which overtime should be scheduled in order to minimize total cost for the aggregate plan?
Question: 1. Based on the table, answer the following questions. (1) (2) (3) (4) (5) (6)...
Question: 1. Based on the table, answer the following questions. (1) (2) (3) (4) (5) (6) (7) K L Q MPK APK APL VMPK 0 20 0 - - - - 1 20 50 100 2 20 150 200 3 20 300 300 4 20 400 200 5 20 450 100 6 20 475 50 7 20 475 0 8 20 450 -50 9 20 400 -100 10 20 300 -200 11 20 150 -300 A firm’s product sells for...
Trials 1 2 3 4 5 6 Mass m(kg) 100 150 200 250 300 350 A(m)...
Trials 1 2 3 4 5 6 Mass m(kg) 100 150 200 250 300 350 A(m) 0.0248 0.0155 0.0306 0.0330 0.0312 0.0682 B(rad/s) 9.50 7.89 6.85 6.17 5.65 5.25 C(rad) 3.29 0.352 4.60 3.57 4.00 4.71 T(s) f (Hz) Question: Using your values of A, B, and C determine the frequency and period of oscillation. Record the period T and frequency f of this motion in your data table; show work.
1)Electrical resistance for a wire of any size can be calculated using the relation: R =...
1)Electrical resistance for a wire of any size can be calculated using the relation: R = pL/A where R = resistance ?, p = resistivity (?-cm), L = wire length (cm), p = 112 u? cm. For a 10-m length of 16-gauge (diameter = 1.291 mm) nichrome wire, find the resistance. If a current of 4 A flows in the wire, find the voltage drop and power dissipation. 2)A standard power value for a household incandescent lightbulb is 60 W....
1. A long solenoid with a diameter of 10 cm has 200 turns/cm. If the current...
1. A long solenoid with a diameter of 10 cm has 200 turns/cm. If the current is decreased at a rate of 3 mA/s, what is the magnitude of the induced electric field (in mV/m), 6 cm from the axis of the solenoid? A. 0.2 B. 0.1 C. 0.3 D. 0.4 2. A series RL circuit with R = 40 Ω and L = 10 H has a constant voltage V = 100 V applied at t = 0 by...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT