The lead storage batteries "A" and "B" are connected in parallel. "A" has an open circuit voltage of 12 V and an internal resistance of 0.2 ohm. Battery "B" has an open circuit voltage of 12.2 V and an internal resistance of 0.3 ohm. If the two batteries together delivers power to a 0.5 ohm power resistor, neglecting effects of temperature, how much current is contributed by battery "A"? Please provide equations and all steps to a correct solution. Thanks.
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