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The lead storage batteries "A" and "B" are connected in parallel. "A" has an open circuit...

The lead storage batteries "A" and "B" are connected in parallel. "A" has an open circuit voltage of 12 V and an internal resistance of 0.2 ohm. Battery "B" has an open circuit voltage of 12.2 V and an internal resistance of 0.3 ohm. If the two batteries together delivers power to a 0.5 ohm power resistor, neglecting effects of temperature, how much current is contributed by battery "A"? Please provide equations and all steps to a correct solution. Thanks.

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