Question

A 50 Hz single –phase inverter of 80% quasi –square waveform
output voltage

supplies a 40 mH with 8 ohm from a 200 V dc source. Plot the
relevant

waveform and find:

1- The rms voltage of the load and its components.

2- The expression of load current variation.

Answer #1

A single-phase full-bridge inverter supplies a load of 10 W in
series with an inductance of 31.8 mH. The inverter is supplied by a
380 VDC source.
(a) Sketch the inverter circuit as described above.
(b) Calculate the rms value of the fundamental (n = 1) of the
inverter output voltage assuming it is a square-wave.
(c) Assuming a quasi square-wave output voltage waveform with a
delay angle of 45°, calculate the rms value of the fundamental and
the two...

A single-phase full-bridge inverter has RLC load of R = 4 ? and
L = 35 mH
and C = 155 ?F. The dc input voltage is 230 V and the output
frequency is 50 Hz.
(a) Find an expression for load current up to fifth harmonic.
(b)Calculate rms value of fundamental load current
(c) The power absorbed by load and the fundamental power
(d)The rms and peak current of each IGBT
(e) Conduction time of IGBTs and diodes if...

A single?phase half?bridge inverter is used to power a purely
inductive load of 100mH. The inverter is supplied from a dc source
of 300V, and is operated at a frequency of 50Hz using square?wave
modulation.
a) Determine the values of the fundamental, 3rd, 5th and 7th
harmonic load current components.
b) Determine the load current THD value.

For a single phase square wave inverter of 300V input supply
voltage 60Hz, calculate the 6th, harmonic that will be generated at
the output of the inverter

For a single phase square wave inverter of 300V input supply
voltage 60Hz, calculate the 3rdd, harmonic that will be
generated at the output of the inverter

A single phase half wave converter in is operated from a 120 V
60 Hz supply and a freewheeling diode is connected across the load.
the load consists of series connected resistance R= 10 ohm
inductance L= 5mH and battery E=20V. Express the instantaneous
output voltage in fourirer series and determine the rms value of
the lowest order output harmonic current.

The parameters of a 3-phase, 4-pole, 50 Hz,
Y-connected, wound-rotor induction motor are listed below. These
are the default values of the "Asynchronous Machine" model in
MATLAB Simulink. r1=0.5968 Ω; r2=0.6258 Ω; L1=0.0003495 H;
L2=0.005473 H; Lm=0.0354 H; Stator line voltage = 400 V rms. The
motor for rotor speeds nm= 0 to 1500 rpm.
X1= 0.1097 ohm, X2= 1.719 ohm , Xm= 11.12 ohm, RTH =
0.5853 , XTH = 0.1395 and
VTH = 230.82 V.
Suppose the motor...

A single phase 3kVA 480/240 V 50 Hz transformer has the
following parameters:
High voltage side: r1 = 0.25 Ω Xl1 =
0.75
Low voltage side: r2 = 0.05 Ω Xl2 =
0.18
a) Draw the equivalent circuit with
quantities referred to the low voltage side;
b) Determine the voltage regulation when the transformer
is supplying full load at 240 Vrms
and 0.9 power factor lagging;
c) If the load terminals are accidentally
short-circuited determine the currents in the high...

The parameters of a 3-phase, 4-pole, 50 Hz, Y-connected,
wound-rotor induction motor are listed below. These are the default
values of the “Asynchronous Machine” model in MATLAB Simulink.
r1=0.5968 ?; r2=0.6258 ?; L1=0.0003495 H; L2=0.005473 H; Lm=0.0354
H; Stator line voltage = 400 V rms. The motor for rotor speeds nm=
0 to 1500 rpm. X1= 0.1097 ohm, X2= 1.719 ohm , Xm= 11.12 ohm, RTH =
0.5853 , XTH = 0.1395 and VTH = 230.82 V. Suppose the motor...

A 10-kVA, 250 / 100-V, 50-Hz single-phase transformer gave the
following open and short circuit test results:
Open circuit test: 250 V, 2.6 A, power factor: 0.3 on HV
side.
Short circuit test: 18 V, 80 A, input power: 240 W on HV
side.
Calculate the following:
4.1 The equivalent circuit parameters of the transformer. (6)
4.2 The efficiency at full load unity power factor. (NB the test
current is not at full load) (6)
4.3 The load at which...

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