Question

I have an 4-bit unsigned Binary adder that performs F=A+B with carry in and carry out,...

I have an 4-bit unsigned Binary adder that performs F=A+B with carry in and carry out, I have to draw the smallest circuit using the adder and whatever other combinational logic gates I need to perform the 4-bit function below on 2's complement numbers A and B

F=A+B if ADD=1,

F=A-B if ADD=0

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Answer #1

The circuit is shown below

Lets see what happend when ADD = 1

When ADD = 1, the output of the NOT gate will be 0. So the carry in bit Cin will be zero. Also the one input to each EX - OR gate will be 0. So the number B will go as it is to the adder and the numbers A and B will get added. We will get the output A + B

Lets see what happend when ADD = 0

When ADD = 0, the output of the NOT gate will be 1. So the carry in bit Cin will be 1.  Also the one input to each EX - OR gate will be 1. So the number B will go as its one's complement. Now the Cin bit is also 1. So effectively we get the two's complement of B as the second number. Now A and the two's complement of B will be added. This is nothing but A - B . We will get the output A - B

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