Question

Using MATLAB The range of an object shot at an angle θ (with respect to x-axis),...

Using MATLAB

The range of an object shot at an angle θ (with respect to x-axis), with the initial velocity of V0 (in the absence of air resistance), is calculated by the following formula: range=(Vo^2/g)(sin(2theta)) where (0<=theta<=pi/2) And the trajectory of object is given by:     h=tan(theta).x-(g/2Vo^2*cos^2(theta)).x^2 .Where h is the height of the object at each x location and g = 9.81 m/s2.

a) Using π/8 increment size for the angle and V0 = 10 m/s, plot the trajectories of the object in one figure with respect to x.

Hint: follow these steps:

1) For each value of θ find the range.

2) Create x as a vector starting from 0 to the computed range.

3) Compute h using θ and x from steps 1 and 2.

4) Plot h as a function of x.

5) Use hold on for the next plot (Use different colors for the plots and don’t forget to put legends and labels).

b)Create a vector for θ including 100 equally-spaced elements, and determine at which angles the maximum and minimum ranges occurs.

c)What is the max. height of the object at the angle determined in part b.

Homework Answers

Answer #1

%get the initial velocity

v0=input(‘Enter the initial velocity’)

Theta=0:pi/100:pi/2;

g=9.81;

% calculate the range

Range=(v^2/g)*(sin(2*theta));

maxRange=0;

in=0;

% find the maximum range

for i=1:length(Range)

             if Range>max Range

                             maxRange=Range;

                             in=I;

                 end

end

% find the maximu angle

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