You have
$500,000
in an IRA (Individual Retirement Account) at the time you retire. You have the option of investing this money in two funds: Fund A pays
3.6%
annually and Fund B pays
6.1%
annually. How should you divide your money between Fund A and Fund B to produce an annual interest income of
$26,000?
Let the investment in fund-A is X.
Therefore, the investment in fund-B is (500,000 – X).
As per the condition given,
X × 3.6% + (500,000 – X) × 6.1% = 26,000
X × 0.036 + (500,000 – X) × 0.061 = 26,000
0.036X + 500,000 × 0.061 – 0.061X = 26,000
0.036X – 0.061X + 30,500 = 26,000
-0.025X = 26,000 – 30,500
-0.025X = - 4,500
0.025X = 4,500
X = 4,500 / 0.025
= 180,000
Hence,
500,000 – X = 500,000 – 180,000 = 320,000
Answer: Fund-A investment is $180,000; Fund-B investment is $320,000.
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