A worker invests £1000 at the end of each year for 10 years in a project that grows at an annually compounded rate of 6%.
Solution :-
(i)
Rate of Interest = 6%
Annual Deposit = $1,000
Time = 10 Years
Terminal Value of Investment = $1,000 * PVAF ( 6% , 10 )
= $1,000 * [ ( 1 + 0.06 )10 - 1 ] / 0.06
= $16,666.67 * [ 1.7908 - 1 ]
= $13,180.79
(ii) If the Payment Deposit in the beginning of the Year
Future Value = $1,000 * FVAF ( 6% , 10 ) * ( 1 + 0.06 )
= $1,000 * [ ( 1 + 0.06 )10 - 1 ] * 1.06 / 0.06
= $13,180.79 * 1.06
= $13,971.64
Answer changed by $13,971.64 - $13,180.79 = $790.85
(iii)
The Amount that need to be borrowed today to pay $1,000 for 10 Years
= $1,000 * PVAF ( 6% , 10 )
= $1,000 * [ 1 - ( 1 + 0.06)-10 ] / 0.06
= $16,667 * [ 1 - 0.5583 ]
= $7,360.09
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