sample of size 36, the 95% confidence interval for the population mean is 64.90, 69.30. The sample mean is:
66.04 |
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None of the choices is correct. |
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67.10 |
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63.10 |
Given:
(Since, sample size >30, z-scores are used)
Significance level =95%
SInce confidence interval is a two-tailed test, we need to find:
Confidence interval is computed using the following formula:
We will make two equations
.............................Equation 1
.............................. Equation 2
Let us consider
Therefore, the equations are
Solving these two, We get, Y = 2.2
Thus,
Answer is OPTION C
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