With the estimates shown below, Sarah needs to determine the trade-in (replacement) value of machine X that will render its AW equal to that of machine Y at an interest rate of 9% per year. Determine the replacement value.
Machine X | Machine Y | |
Market Value, $ | ? | 94,000 |
Annual Cost, $ per Year | −57,500 | −40,000 for year 1,increasing by 2000 per year thereafter. |
Salvage Value | 19,500 | 21,000 |
Life, Years | 3 | 5 |
The replacement value is $ ________.
We need to calculate preset value of machine Y
Year | Cash Flow | |||||
investment | annual cost | salvage value | net cash flow | discount factor | present worth | |
0 | -94000 | -94000 | 1.00000 | -94,000.00 | ||
1 | -40000 | -40000 | 0.91743 | -36,697.25 | ||
2 | -42000 | -42000 | 0.84168 | -35,350.56 | ||
3 | -44000 | -44000 | 0.77218 | -33,976.07 | ||
4 | -46000 | -46000 | 0.70843 | -32,587.56 | ||
5 | -48000 | 21000 | -27000 | 0.64993 | -17,548.15 | |
-250,159.59 |
AW of machine Y = present worth * (A/P, 9%, 5yrs = -250159.59 * 0.257092 = -64314.029
Now AW of machine X
Let market value be m then
AW of machine X = -m*(A/P, 9%, 3 yrs) - 57500 + 19500 (A/F, 9%, 3 yrs)
= -m*0.395055 -57500 + 19500 * 0.305055
= -m*0.395055 - 51551.42
To find M
AW of machine X = AW of machine Y
0.395055*m + 51551.42 = 64314.029
0.395055m = 12762.60
m = 32305.88
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