Player 2 | ||||
A | B | C | ||
A | 3,5 | 4,2 | 1,1 | |
Player 1 | B | 5,3 | 3,6 | 4,5 |
C | 6,2 | 8,1 | 7,0 |
In the matrix game above, what is the payoff that Player 2 receives in the nash equilibrium outcome?
Answer :
Here Player 1 is a row player and Player 2 is a column player.
From the game matrix we see that Player 1's strategy of playing C dominates over both A and B.
From Player 1's perspective : Payoff in A = 3 , 4 , 1 (Note : 6 > 3 , 8 > 4, 7 >1 when compared to strategy C)
Payoff in B = 5, 3 , 4 (Note : 6 > 5 , 8 >3 , 7 > 4 when compared to strategy C)
Payoff in C = 6, 8, 7
So from that we see that payoffs in C are higher than their corresponding payoffs in A and B both. Thus C is a dominant strategy and Player 1 will play C no matter what so we can delete A and B rows from the game.
The reduced game would look like:
A | B | C | |
C | 6,2 | 8,1 | 7,0 |
where Player 1 is the row player and Player 2 is the column player.
In this scenario it is best for Player 2 to play strategy A (since Player 1 always plays C).
For Player 2 : A has a payoff of 2 , B has 1 and C has 0. Thus A gives the highest payoff and Player 2 will play A.
Thus the nash equilibrium of this game is (Player 1, Player 2) = (6 , 2) : So in nash equilibrium Player 1 gets a payoff of 6 and Player 2 gets a payoff of 2
Answer : Player 2 receives a payoff of 2 in the nash equilibrium outcome.
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