Given the following three alternatives, the equation for capitalized cost (CW) of alternative F at i=10% is:
Alternative | E | F | G |
First Cost, $ | -50,000 | -300,000 | -900,000 |
AOC, $ per year | -30,000 | -10,000 | -3,000 |
Salvage value, $ | 5,000 | 70,000 | 200,000 |
Life, years | 2 | 4 |
∞ |
Group of answer choices
A.) CW(F) =( -300,000(A/P,10%,4) – 10,000 + 70,000(P/F,10%,4) )/0.1
B.) CW(F) =( -300,000(P/A,10%,4) – 10,000 + 70,000(P/F,10%,4) )/0.1
C.) CW(F) =( -300,000(A/P,10%,4) – 10,000 + 70,000(A/F,10%,4) )(0.1)
D.) CW(F) =( -300,000(A/P,10%,4) – 10,000 + 70,000(A/F,10%,4) )/0.1
Calculation of Capitalized Cost (CW) Using the Equation
Capitalized Cost (CW) means present worth of cash flows which go on for infinite period of time. This analysis used in basically work project like Dam Bridges & Park.
The Basic Equation of Capitalized cost (CW) is
P = A/i
That Means A = Pi or P = A/i
Here Given Date
In F First Cost $ (FC) = -300000
Annual Operating Cost (AOC = -10000
Salvage Value (SV) = 70000
Life Span Year = 4
Calculation of Capitalized Cost (CW) using the Equation is
= FC(AP,10% 4) - AOC+SV (A/F, 10% 4)/0.1
= -300000 (AP, 10% 4) - 10000+70000(A/F, 10%, 4)/0.1
In Your Option Correct Answer is - D
That is -300000 (AP, 10% 4) - 10000+70000(A/F, 10%, 4)/0.1
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