A machine that costs $20,000 and has a 10-year life and a $2000 salvage value. If straight-line depreciation is used, what is the accumulated depreciation for the machine at the end of the 6th year?
Ans: The accumulated depreciation for the machine at the end of the 6th year is $10,800
Explanation:
Cost of the asset ( P ) = $20,000
Salvage value ( F ) = $2,000
Number of year ( n ) = 10
Annual depreciation amount = P - F / n
= ( $20,000 - $2,000) / 10
= $18,000 /10
= $ 1800
The accumulated depreciation for the machine at the end of the 6th year = $1800 * 6 = $10,800
End of the Year | Depreciation Amount | Book Value = Previous year book value - Current year depreciation amount |
0 | -- | $20,000 |
1 | 1800 | 18200 |
2 | 1800 | 16400 |
3 | 1800 | 14600 |
4 | 1800 | 12800 |
5 | 1800 | 11000 |
6 | 1800 | 9200 |
7 | 1800 | 7400 |
8 | 1800 | 5600 |
9 | 1800 | 3800 |
10 | 1800 | 2000 |
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