Question

Minimize the following cost function ; TC = 1/3q^3 - 8 . 5q^2 + 60q+27

Minimize the following cost function ; TC = 1/3q^3 - 8 . 5q^2 + 60q+27

Homework Answers

Answer #1

TC = q3/3  - 8 .5q2 + 60q + 27  

dTC/dq = 3q2/3 - 17q + 60  

= q2 - 17q + 60  

put dTC/dq = 0  

q2 - 17q + 60 = 0  

q2 - 5q - 12q + 60 = 0  

q(q - 5) -12(q - 5) = 0  

(q - 12)(q - 5) = 0  

q - 12 = 0 or q - 5 = 0

q = 12 or q = 5

SOC  

d2TC/dq2 = 2q - 17  

at q = 5  

d2TC/dq2 = 2(5) - 17 = 10 - 17 = - 7

d2TC/dq2 < 0

Therefore cost is maximum at q = 5

at q = 12  

d2TC/dq2 = 2(12) - 17 = 24 - 17 = 7

d2TC/dq2 > 0  

so cost is minimum at q = 12

Minimumm TC = (123)/3 - 8.5(12)2 + 60(12) + 27  

= 576 - 1224 + 720 + 27

= 1323 - 1224

= 99

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