For alternatives shown in the table below you are trying to
decide which alternative you should choose based on their
capitalized costs (CC). Use an interest rate of 10% per year.
Machine A | Machine B | |
First cost (AED) | 20,000 | 240,000 |
Annual maintenance cost per year, AED | 5,000 | 2,300 |
Periodic cost every 10 years , AED | - | 10,000 |
Salvage cost | 2000 | -- |
Life , years | 4 | ∞ |
Match the closest correct answers for the below questions:
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Let us consider alternative B
Calculate the present value of the maintenance costs for Alternative B.
Annual maintenance cost=O&M=-2300 AED
Periodic Cost=P=-10000 AED
Initial Cost=Co=-240000 AED
Present Value of maintenance cost for alternative B=O&M/i=-2300/10%=-23000 AED
Correct option is H) -23000
Calculate the Annual value of the periodic costs for Alternative B
Annual Cost of periodic Cost for alternative B=P*(A/F,10%,10)
Annual Cost of periodic Cost for alternative B=-10000*0.062745=-627.45 AED or -627.5 AED Correct option is E) -627.50
Calculate CC of Alternative B
Capitalized Cost of alternative B=Initial Cost+PV of maintenance cost+Annual periodic cost/i
Capitalized Cost of alternative B=-240000-23000-627.5/10%=-269275 AED
Correct option is C) -269275
Calculate the CC of Alternative A
Annualized Cost of alternative A=-20000*(A/P,10%,4)-5000+2000*(A/F,10%,4)
Annualized Cost of alternative A=-20000*0.315471-5000+2000*0.215471=-10878.48 AED
Capitalized cost of alternative A=Annualized Cost/i=-10878.48/10%=-108784.80 or -108,784 AED
Correct option is I) -108784
Which alternative should be selected?
Absolute value of capitalized is lower in case of alternative A. It is better.
Alternative A should be selected
Correct option is A) Alternative A
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