A random survey of enrollment at 10 community colleges across the United States yielded the following figures: 1,468; 1,464; 5,041; 1,450; 4,591; 5,932; 2,101; 2,029; 3,846; and 2,101. What is the 99% Error Bound (EBM) of the population mean?
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The answer is 3002.3 ± 1,305.241
Solution
Count:10 (How many numbers)
Sum: 30023(All the numbers added up)
Mean:3002.3(Arithmetic mean = Sum / Count)
Now calculate the Variance
Sum of Differences2: 25677312.1 (Add up the Squared Differences)
Variance: 2567731.21 (Sum of Differences2 / Count)
Hence Standard Deviation: 1602.414182 (The square root of the Variance)
Now,
X̄ ± Z× | σ |
√n |
Where Z is the Z-value for the chosen confidence level, X̄ is the sample mean, σ is the standard deviation, and n is the sample size. Assuming the following with a confidence level of 99%:
X̄ = 3002.3
Z = 2.576 ( as per Z table )
σ = 1602.41
n = 10
The confidence interval is:
3002.3 ± 2.576*(1602.41/√10)
i.e. 3002.3 ± 1,305.241
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