MC1= 20 + 2Q1
MC2= 10 + 5Q2
Assume that the inverse demand curve is P = 500-Q.
What is the maximum profit? Assume total Fixed Costs for plant 1 (TFC1) = $0 and Total Fixed Costs for plant 2 (TFC2) = $0.
P = 500 - Q
Total revenue (TR) = PQ = 500Q - Q2
Marginal revenue (MR) = dTR/dQ = 500 - 2Q
MC1 = 20 + 2Q1, therefore Q1 = (MC1 - 20)/2 = 0.5MC1 - 10
MC2 = 10 + 5Q2, therefore Q2 = (MC2 - 10)/5 = 0.2MC2 - 2
Since Q = Q1 + Q2,
Q = 0.5MC1 - 10 + 0.2MC2 - 2
Q = 0.5MC1 + 0.2MC2 - 12
Setting MC1 = MC2 = MC,
Q = 0.5MC + 0.2MC - 12
Q = 0.7MC - 12
0.7MC = Q + 12
MC = (Q + 12)/0.7
Profit is maximized by equating MR and MC.
500 - 2Q = (Q + 12)/0.7
350 - 1.4Q = Q + 12
2.4Q = 338
Q = 140.83
P = 500 - 140.83 = 359.17
MC = (140.83 + 12)/0.7 = 152.83/0.7 = 218.33
Maximum profit = Q x (P - MC) = 140.83 x (359.17 - 218.33) = 140.83 x 130.84 = 19,834.50
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