2. Exercise 4.2 Dismiss All Please Wait . . . Please Wait... The Pilot Pen Company has decided to use 15 test markets to examine the sensitivity of demand for its new product to various prices, as shown in the following table. Advertising effort was identical in each market. Each market had approximately the same level of business activity and population. Complete the following worksheet and then estimate the demand function for Pilot's new pen using a linear regression model.
Points:
Points: Close Explanation Explanation: What is the standard error of the estimate (sese )? 105.103 1.407 1.674 Points: Close Explanation Explanation: What is the estimate of the standard deviation of the estimated slope (sbsb )? 0.025 0.030 1.896 Points: Close Explanation Explanation: Can you reject the hypothesis (at the 0.05 level of significance) that there is no relationship (i.e., β=0β=0 ) between the price and quantity variables? (Hint: t0.025,13=2.16t0.025,13=2.16 ) No Yes Points: Close Explanation Explanation: Complete the following worksheet and then use it to calculate the coefficient of determination.
Points: The coefficient of determination (r2r2 ) is selector 1
Points: Close Explanation Explanation: What is the price elasticity of demand at a price of 50 cents? 0.03 -0.02 -0.50 -0.46 |
a. The regression model expresses the demand (quantity sold) for pens as a function of price:
Qi= [\alpha] + [\beta] P1+ [\varepsilon] i
We can estimate the model to get predictions: Q i = [\alpha] + [\beta] P i.
We get a = 28 . 915 and b =-0.191
Hence, we predict that a one-cent increase in the price of a pen will lead to a decrease in sales of 191 units, on average.
C, In the model the Price elasticity of demand is given by
ED= ( [\delta] QP) / ( [\delta] PQ) = [\beta] (P/Q)
Which can be estimated by ED= [\beta] (P/Q)
At P = 50 , Q = a + b (50) = 19 . 363 .
Thus we have ED= (-0.191) 50/ 19.363 [\approx] -0.493
Therefore, we predict that a 1% increase in price will lead to a 0.493% decrease in sales, on average, at an initial price of $ 0.50.
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