Consider a modified version of the very famous tictactoe game in which player 1 moves, then player 2 moves, and then player 3 moves and the game ends. The number of strategies for player 1, 2, and, 3 are respectively:
a. 
9, 72, and 504. 

b. 
None of the available options in this list. 

c. 
9, 9, and 9. 

d. 
9, 8, and 7. 
Answer is option A)
since first player can select any of the 9 positions available,
So he has 9 strategies.
Now the second player moves, & he face total 9 nodes,
& At each node, he can select any of the 8 positions vacant .
So total strategies = 8*9 = 72
( 8 strategies at each of 9 nodes)
Now P3 moves ,
Now he faces total 8*9 = 72 nodes
At each node, he have 7 positions vacant,
So 7 strategies available at each of 72 nodes
Total strategies = 7*72
= 504
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