Q6. The monopolist produces and distributes the Cartoon
Magazine. Demand is given by P = 1200-10Q. The cost function is TC
= 200Q+15Q2
Your work:
a. What output maximizes its profit?
b. What is the profit-maximizing price?
a. What output maximizes its profit?
Monopolist maximises it's profit where MR equals MC.
MR can be find by taking derivative of total revenue.
Total revenue =Price *quantity
=1200-10Q*(Q)
=1200Q-10Q^2.
MR =dTR /dQ
=1200-20Q.
MC can be find by taking derivative of total cost.
MC =dTC /dQ
=200+30Q.
Now, profit maximising quantity is where,
MR =MC
1200-20Q=200+30Q
1200-200=30Q+20Q
1000=50Q
1000/50=Q
20=Q.
So profit maximising quantity is 20 units.
b. What is the profit-maximizing price?
Put Q=20 in inverse demand function to get price.
P=1200-10Q
=1200-10(20)
=1200-200
=1000.
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